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本篇介紹AJAX應用在PHP&MYSQL的實例,實作可以在W3School操作,本篇因不做跨網域所以僅介紹程式碼。
HTML程式碼:- <html>
- <head>
- <script>
- function showUser(str)
- {
- if (str=="")
- {
- document.getElementById("txtHint").innerHTML="";
- return;
- }
- if (window.XMLHttpRequest)
- {// code for IE7+, Firefox, Chrome, Opera, Safari
- xmlhttp=new XMLHttpRequest();
- }
- else
- {// code for IE6, IE5
- xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
- }
- xmlhttp.onreadystatechange=function()
- {
- if (xmlhttp.readyState==4 && xmlhttp.status==200)
- {
- document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
- }
- }
- xmlhttp.open("GET","getuser.php?q="+str,true);
- xmlhttp.send();
- }
- </script>
- </head>
- <body>
- <form>
- <select name="users" onchange="showUser(this.value)">
- <option value="">Select a person:</option>
- <option value="1">Peter Griffin</option>
- <option value="2">Lois Griffin</option>
- <option value="3">Glenn Quagmire</option>
- <option value="4">Joseph Swanson</option>
- </select>
- </form>
- <br>
- <div id="txtHint"><b>Person info will be listed here.</b></div>
- </body>
- </html>
複製代碼 PHP程式碼:- <?php
- $q = intval($_GET['q']);
- $con = mysqli_connect('localhost','peter','abc123','my_db');
- if (!$con)
- {
- die('Could not connect: ' . mysqli_error($con));
- }
- mysqli_select_db($con,"ajax_demo");
- $sql="SELECT * FROM user WHERE id = '".$q."'";
- $result = mysqli_query($con,$sql);
- echo "<table border='1'>
- <tr>
- <th>Firstname</th>
- <th>Lastname</th>
- <th>Age</th>
- <th>Hometown</th>
- <th>Job</th>
- </tr>";
- while($row = mysqli_fetch_array($result))
- {
- echo "<tr>";
- echo "<td>" . $row['FirstName'] . "</td>";
- echo "<td>" . $row['LastName'] . "</td>";
- echo "<td>" . $row['Age'] . "</td>";
- echo "<td>" . $row['Hometown'] . "</td>";
- echo "<td>" . $row['Job'] . "</td>";
- echo "</tr>";
- }
- echo "</table>";
- mysqli_close($con);
- ?>
複製代碼 參考:W3SCHOOL |
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